Math, asked by Abrarmirza, 1 year ago

find the ratio of sinx,cosx,tanx,where x=45°

Answers

Answered by sakshi213
1
sin 45 =1/rt2
cos 45=1/rt2
tan 45 =1
Answered by tardymanchester
0

Answer:

1) sin45^{\circ}=1:\sqrt{2}

2) cos45^{\circ}=1:\sqrt{2}

3) sin45^{\circ}=1:1

Step-by-step explanation:

Given : Function - sinx, cosx, tanx and x=45°

To find: Ratio of function

1) sinx

x=45^{\circ}\rightarrow sin45^{\circ}=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}

Ratio of sin45^{\circ}=1:\sqrt{2}

2) cosx

x=45^{\circ}\rightarrow cos45^{\circ}=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}

Ratio of cos45^{\circ}=1:\sqrt{2}

3) tanx

x=45^{\circ}\rightarrow tan45^{\circ}=1

Ratio of tan45^{\circ}=1:1



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