Math, asked by rithwikreddy313, 9 months ago

find the ratio of the area of a to the area of the is 4 : 5 find the ratio of the area of B to the area of C is 1 : 3 find the ratio of the area of A to rhe area of C​

Answers

Answered by laxmipanda233
1

Given,

A:B=2:3

A=2x,B=3x

B:C=4:5

B=4x,C=5x

Now in above two ratios in first B has 3x value and in second B has 4x value. Take LCM of 3x, 4x. You have 12x.

To make the value of B in first ratio to 12x . Multiply first ratio with 4x and in other ratio with 3x.

You have,

A:B=8x:12x and B:C=12x:15x

On combining these two,

A:B:C=8x:12x:15x

Now,

C:D=6:8

C=6x,D=8x

Now in above two ratios in first C has 15x value and in second C has 6x value. Take LCM of 15x, 6x. You have 30x.

To make the value of C in first ratio to 30x . Multiply first ratio with 2x and in other ratio with 5x.

A:B:C=16x:24x:30x

C:D=30x:40x

On combining these two,

A:B:C:D=16x:24x:30x:40x

If eliminate x.

We have A:B:C:D=16:24:30:40

You can also divide ratio by 2 because all terms have 2 in common.

Answered by Anonymous
61

Given:

A:B=2:3

A=2x,B=3x

B:C=4:5

B=4x,C=5x

Now in above two ratios in first B has 3x value and in second B has 4x value. Take LCM of 3x, 4x. You have 12x.

To make the value of B in first ratio to 12x . Multiply first ratio with 4x and in other ratio with 3x.

We have,

A:B=8x:12x and B:C=12x:15x On combining these two,

A:B:C=8x:12x:15x

Now,

C:D=6:8

C=6x,D38x

Now in above two ratios in first C has 15x value and in second Chas 6x value. Take LCM of 15x, 6x. You have 30x.

To make the value of C in first ratio to

30x. Multiply first ratio with 2x and in

other ratio with 5x.

A:B:C=16x:24x:30x

C:D=30x:40x

On combining these two,

A:B:C:D=16x:24x:30x:40x

If eliminate x.

We have A:B:C:D=16:24:30:40

You can also divide ratio by 2 because all terms have 2 in common.

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