Question

Find the ratio of the areas of the squares PQRS to that of ABCD where PQ=9cm and AB=5cm

Answer 1

Answer:

The area of a square is the square of its dimensions.

The ratio of the area of PQRS to ABCD is 25 : 81

The side lengths of the squares are given as:

PQ=9cm ----- square PQRS

AB=5cm --- square ABCD

The area of square PQRS is:

$A_{1} =PQ^2$

So, we have:

$A_{1} =81cm^2$

The area of square ABCD is:

$A_{2} = AB^2$

So, we have:

$A_{2} =25cm^2$

The ratio of the area of PQRS to ABCD is:

25cm² : 81cm²

Hence, the ratio of the area of PQRS to ABCD is 25 : 81