Question

. Find the ratio of the areas of the triangles with sides 11 cm, 17 cm, 22 cm and 22 cm, 34 cm, 44 cm.​

Answer 1

sorry beacuse I do not know

Answer 2

Answer:

Triangle 1

side 11. ,17, and 22

semi-permanent= a+b+c /2

11+17+22/2. = 50/2

25

Area of triangle =√{s(s-a) (s-b) (s-c)}

√25(25-11) (25-17). (25-22)

√25 ×14×8×3

20√21

Triangle 2

side 22, 34 and 44

semi-permanent a+b+c/2

22+34+44/2

100/2

50

Area of triangle√{(s-a). (s-b). (s-c)}

√ 50(50-22) (50-34). (50-44)

√50×28×16×6

80√21

Ratio of triangle= 20√21 / 80√21

1:4