Question

Find the ratio of the areas of the yellow region to the red region in the given figure consisting of right triangles?

Answer 1

Step-by-step explanation:

lets take the whole traiangle as ABC

pls refer the above attachment

area red part = 96 - 6 = 90 sq cm

yellow part = 6 cm [ done in attachment ]

ratio = 90 /6 = 10 /1 or 15 : 1

aditional info :

sin 37 ° = 3 / 5

tan 37 ° = 3 / 4

cos 37° = 4/5

you have to remember this relations of trigonometry in higer class (11 & 12 )