find the ratio of the areas of two circles circumscribed and inscribed in an equilateral triangle
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Answer:
1:4
Step-by-step explanation:
Let "s" be the area of the small circle and "b" for the big circle.
Ratio = Area of small circle / Area of big circle = sb
The radius of the big circle is twice the radius of the small circle, so R=2r.
Substituting the radius, Ratio = π∗r2π∗R2 = π∗r2π∗(2r)2 = 14 = 1:4
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