Question

Find the ratio of the boundaries of a circular field of radius 50m and of a square field of side 22 m

Answer 1

Step-by-step explanation:

Ratio =(2 x pi x 50)/4 x 22 = 2 x (22/7) x 50 x (1/22 x4)

=25 / 7

square : circle

=7:25

Answer 2

$\large \tt AHOY!! \:$

given :-

radius of the circular field = 50m

and side of the square field = 22m

we have to find the ratio between the perimeter (boundary) of both fields.

circumference (boundary) of the circular field = 2πr

= 2 × 22/7 × 50

= 44/7 × 50

= 2200/7m

perimeter of the square field = 4 × side

= 4 × 22

= 88m

therefore ratio between the boundary of the both field :-

=> 2200/7/88

=> 2200/7 × 1/88

=> 25/7

=> 25 : 7

hence, the ratio between them is 25 : 7

$\large \tt HOPE \: THIS \: HELPS!!$