Question

Find the ratio of the boundaries of a circular field of radius 50meter and of a square field of side 22m

Answer 1

boundry of circular field is =2pir=2200/7
and boundry of square field is =4a=88
then ratio is 2200/7/88=25:7

Answer 2

Hey Mate,

Given,

Radius of Circular Field = 50 m

Side of Square Field      = 22 m

When we are talking about boundaries, we are indirectly talking about perimeter.

Perimeter of a circle has a special name given to it, i.e., circumference.

Therefore,

Circumference of a Circle = 2πr

Circumference of the Circle = 2 x 3.14 x 50

Circumference of the Circle = 100 x 3.14

Circumference of the Circle = 314 m

Perimeter of a Square = 4s ( Where "s" is the side of a Square )

Perimeter of the Square = 4 ( 22 )

Perimeter of the Square = 88 m

Hence, Ratio of the boundaries of the circular field and of the square field :-

= 314 : 88

= 157 : 44

Therefore, the ratio of the boundaries of a circular field of radius 50 m and of a square field of side 22 m is 157 : 44.

Hope it Helps!