Question

find the ratio of the boundaries of a circular field of radius 70m and a square field of side 22m ​

Answer 1

Perimeter of circular field =

$2\pi r = 2 \times \frac{22}{7} \times 70 = 440 {m}^{2}$

Perimeter of Square field = 4a = 4 × 22 = 88 m^2

Ratio = 440 / 22 = 20 : 1

Answer 2

circumference of circle= 2πr = 2 ×22/7× 70= 440m

perimeter of square= 4×side= 4×22=88m

ratio=440/88 =5/1 =5:1