Question

find the ratio of the curved surface areas of two cones if their diameters of the bases are equal and slant heights are in the ratio 4:3 .solutions

Answer 1

Radius of both the cones =r
Let :-
L1 =4l L2=3l
CSA1 /CSA2= 22/7 ×r ×4l ÷22/7 ×r ×3l
=4l ÷3l
=4/3
=4:3

Answer 2

Answer:

4:3

Step-by-step explanation:

We are given that the diameters of two cones are equal and  slant heights are in the ratio 4:3

Since the diameter is same so the radii will also be the same.

Let the radius be r

Let the ratio be x

So, slant heights are 4x and 3x

Curved Surface of cone with slant height 4x = $\pi r l$

                                                             = $\pi r (4x)$

Curved Surface of cone with slant height 3x = $\pi r l$

                                                             = $\pi r (3x)$

So,  ratio of the curved surface areas of two cones :

$\frac{\pi r (4x)}{\pi r (3x)}$

$\frac{4}{3}$

Thus the ratio of the curved surface areas of two cones is 4:3