Question

Find the ratio of the electric field lines starting from a proton kept first 1
in vacuum and then in a medium of dielectric constant 6.
​

Answer 1

Answer:

Ratio of electric field lines starting from a proton kept in vacuum and in a medium of dielectric constant is 6

Explanation:

Number of field line coming out of the charge is given as

$\phi = \frac{q}{\epsilon_0}$

now we know that we have to find the ratio of number of lines from a proton placed in vacuum and placed in dielectric medium of constant k = 6

so we will have

$\frac{\phi_1}{\phi_2} = \frac{\frac{e}{\epsilon_0}}{\frac{e}{k\epsilon_0}}$

so we will have

$\frac{\phi_1}{\phi_2} = k$

$\frac{\phi_1}{\phi_2} = 6$

#Learn

Topic : Electric Flux

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