Question

Find the ratio of the following:

(a) 63 to 45

(b) 256 to 512

(c) 66 km to 121 km

(d) 3 minutes to 45 minutes

(answer it fast it's urgent and please don't spam otherwise answer will be reported)​

Answer 1

Answer:

SOLUTION:

i) required ratio =\frac{81}{108}=\frac{81\div27}{108\div27}=\frac{3}{4}=3:410881=108÷2781÷27=43=3:4

[HCF of 81 and 108 = 27]

ii) required ratio= \frac{98}{63}=\frac{98\div7}{63\div7}=\frac{14}{9}=14:96398=63÷798÷7=914=14:9

[HCF of 98 and 63=7]

iii) required ratio = =\frac{33}{121}=\frac{33\div11}{121\div11}=\frac{3}{11}=3:11=12133=121÷1133÷11=113=3:11

[HCF of 33 and 121 =11]

iv) required ratio = \frac{30}{45}=\frac{30\div15}{45\div15}=\frac{2}{3}=2:3\4530=45÷1530÷15=32=2:3 

{HCF of 30 and 45= 15]

Step-by-step explanation:

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