Find the ratio of the linear momenta of two particles of masses 1.0 kg and 4.0 kg if their kinetic energies are equal.
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ANSWER::
Let mass of particles be m₁ and m₂ respectively.
m₁ = 1 kg m₂ = 4 kg
Now ,
1/2 m₁v₁² = 1/2 m₂v₂²
m₁/m₂ = v₂²/v₁²
v₂/v₁ = √(m₁/m₂)
v₁/v₂ = √(m₂/m₁)
(m₁v₁) / (m₂v₂) = m₁/m₂ x √(m₂/m₁) = √m₁/√m₂ = √1/√4 = 1/2
(m₁v₁) / (m₂v₂) = 1/2 = 1:2
Hope this helps!
ANSWER::
Let mass of particles be m₁ and m₂ respectively.
m₁ = 1 kg m₂ = 4 kg
Now ,
1/2 m₁v₁² = 1/2 m₂v₂²
m₁/m₂ = v₂²/v₁²
v₂/v₁ = √(m₁/m₂)
v₁/v₂ = √(m₂/m₁)
(m₁v₁) / (m₂v₂) = m₁/m₂ x √(m₂/m₁) = √m₁/√m₂ = √1/√4 = 1/2
(m₁v₁) / (m₂v₂) = 1/2 = 1:2
Hope this helps!
Anonymous:
Nice answer Hemant bhaiyu :p
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