Find the ratio of the no of atoms present in 16g of o2 and 32g of o3
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Answer:
3:4
Explanation:
No. of atoms in 16g of O2 = 3.011×10²³
No. of atoms in 32g of O3 = 4.014×10²³
Ratio= 3 ×10²³ / 4×10²³
=3:4
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