Question

Find the ratio of the number of atoms present in
16 g of O2, and 32 g of O3.
(1) 1:1
(2) 2:1
(3) 1:3
(4) 1:2​

Answer 1

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The answer is option D

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Answer 2

Answer:

1:2

Explanation:

Option ( 4 ).

No. (Number) of atoms = x moles

Avogadro's number = x atomicity

Moles of O2 = 16/32

= 1/2

Moles of O3 = 32/48

=2/3

No. of atom of O2/ No. of atom of O3

=( 1/2 x Na x 2)/(2/3 x Na x 3)

Therefore, Ratio = 1:2.

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