Question

Find the ratio of the pressed exerted by a block of 400N when placed on a table top along its two different sides with dimension 20cm×10cm and 10cm×15cm

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Answer 1

Given

$\sf{ \bull Force= 400 N} \\ \:\: \sf{ \bull D_1=20×10 cm} \\ \: \:\sf{ \bull D_2 = 10 ×15 cm}$

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To find

The ratio of the pressure exerted (P1/P2).

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Topic -

Pressure

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Solution

$\sf{ \implies Dimension_1 = 20×10 cm = 0.2 ×0.1 metre} \\ \\ \sf{ \implies Dimension_2= 15×10 cm = 0.15 × 0.1 metre}$

Pressure formula

${ \underline{ \boxed{\mathtt{P=\frac{F}{A}}}}}$

where

• P denotes pressure
• F denotes force
• A denotes Area

Ratio will be given as :-

$\sf{\dfrac{P_1}{P_2}= \dfrac{\frac{F}{A_1}}{\frac{F}{A_2}}}$

$\sf{\implies\dfrac{P_1}{P_2}= \dfrac{A_2}{A_1}}$

$\sf{\implies\dfrac{P_1}{P_2}=\dfrac{0.15 × 0.1 }{0.2 ×0.1}}$

$\implies \red{ \sf{\dfrac{P_1}{P_2}= \dfrac{3}{4} }}$

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More to Know!

• unit of pressure= Pascal

• pressure is defined as the force applied perpendicular to the surface of objects per unit area.

• 1 Pascal = 1Newton/metre²

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