Question

Find the ratio of the radius of the effort piston and the load piston of a hydraulic machine if a load of 500N

is to be lifted by applying a force of 10N​

Answer 1

Explanation:

Phydraulic=FappliedAapplied=FoutputAoutput

Phydraulic=20N0.05m2=400Nm2=Foutput0.1m2

Foutput=400Nm2⋅0.1m2=40N

You can, of course, simplify this algebraically before plugging the numbers in, to avoid even worrying about the intermediate pressure result:

Foutput=Fapplied⋅AoutputAapplied

Answer 2

Answer:

ii hope it will help you thanks