find the ratio of the the volumes of a cone and cylinder whose base diameter and heights are equal.
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0
Answer:
Step-by-step explanation:
V(cylinder ) = pi×r^2×h
V(cone) = pi×r^2×h/3
V(cone)/V(cylinder) = 1 / 3
where r is the base radius and h is the height.
Answered by
1
1:3 is the answer for this
[tex]1 \div 3 \times \pi \times r {}^{f the co-ordinates of the mid points of the sides of a triangle are (1, 1),
(2, –3) and (3, 4), then find its centroid.} \times h \div \pi \times r {}^{2} \times h[/tex]
ATQ,
radius and height are equal
so all will get canceled and the remaining number is 1divided by 3
we should find ratio
so required ratio is 1:3
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