Question

find the ratio of the volumes of the two cubes whose side are 2.2cm and 1.8cm​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Given:-

• 2 cubes are given in the question
• One cube has side 2.2 cm
• Another has 1.8 cm

Concept:-

Volume of the cubes, surface area and volume

Let's Do!

We know that volume of the cube is $\rm{a^3}$

Where a is the side of the cube.

Cube 1:-

$(2.2)^3 = \rm{Volume \ of \ 1^{st} \ Cube}$

$\rm{= 10.648 \ cm^3}$

Cube 2:-

$(1.8)^3 = \rm{Volume \ of \ 2^{nd} \ Cube}$

$\rm{ = 5.832 cm^3}$

If we keep it simple:-

$2.2:1.8$

$= \dfrac{22}{10}:\dfrac{18}{10}$

Denominator 10 cancels, so the answer is

$\boxed{11:9}$ is the ratio.

Answer 2

Answer:

$\huge \tt given$

• Edge of 1 st cube - 2.2 cm
• Edge of 2 nd cube - 1.8 cm

$\huge \tt \: to \: find$

Ratio of volumes

$\huge \tt \: solution$

So, for finding ratio of volume we have to find the volume

Volume of cube 1

$\sf \implies \: volume \: of \: cube = {edge}^{3}$

$\sf \implies \: volume \: of \: cube \: = {2.2}^{3}$

$\sf \implies \: volume \: of \: cube \: = 10.648 cm$

Volume of cube 2

$\sf \implies \: volume \: of \: cube \: = {edge}^{3}$

$\sf \implies \: volume \: of \: cube \: = {1.8}^{3}$

$\sf \implies \: volume \: of \: cube \: = 5.832 \: cm$

Ratio

$\frac{22}{10} \ratio \frac{18}{10}$

$\frac{11}{9} = 11 \ratio \: 9$