Physics, asked by gudduoraon73461, 11 months ago

Find the ratio of these quantities to the boundary layer thickness δ if the velocity profile within the boundary layer is given by u/u1=sin(πy/2δ) show, by means of a momentum balance, that the variation of the boundary layer thickness δ with distance (x) from the leading edge is given by δ = 4.8(rex) -0.5

Answers

Answered by shipramukherjee
0

Answer:

Solution:

Given:

=> Velocity of sound in gas at 27°C = 330 m/s.

To Find:

=> Velocity at 327°C.

Let velocity at 327°C be x,

So,

\sf{\implies \dfrac{27}{330}=\dfrac{327}{x}}⟹33027=x327

\sf{\implies \dfrac{330 \times 327}{27} = x}⟹27330×327=x

\sf{\implies x = 3996.6\;m/s}⟹x=3996.6m/s

{\boxed{\boxed{\bf{So,\;velocity\;at\;327^{\circ}C=3996.6\;m/s}}}}So,velocityat327∘C=3996.6m/s

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