Find the ratio of these quantities to the boundary layer thickness δ if the velocity profile within the boundary layer is given by u/u1=sin(πy/2δ) show, by means of a momentum balance, that the variation of the boundary layer thickness δ with distance (x) from the leading edge is given by δ = 4.8(rex) -0.5
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Answer:
Solution:
Given:
=> Velocity of sound in gas at 27°C = 330 m/s.
To Find:
=> Velocity at 327°C.
Let velocity at 327°C be x,
So,
\sf{\implies \dfrac{27}{330}=\dfrac{327}{x}}⟹33027=x327
\sf{\implies \dfrac{330 \times 327}{27} = x}⟹27330×327=x
\sf{\implies x = 3996.6\;m/s}⟹x=3996.6m/s
{\boxed{\boxed{\bf{So,\;velocity\;at\;327^{\circ}C=3996.6\;m/s}}}}So,velocityat327∘C=3996.6m/s
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