Question

find the ratio of total kinetic energy to the rotational kinetic energy of a rolling cylinder​

Answer 1

Answer:

ANSWER

Rotational kinetic energy =

2

1

Iω

2

=

2

1

(

2

1

MR

2

)ω

2

v = R × ω

Translational K.E=

2

1

mv

2

⇒ratio=

2

1

mv

2

2

1

(

2

1

mv

2

)

=

2

1