find the ratio of triangle ABC and triangle DEF
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Sol:
Given that D, E and F are the mid-points of BC, CA and AB respectively, then from the mid-point theorem
EF = BC / 2, DE = AB / 2, DF = AC / 2.
But Δ ABC ~ Δ DEF
Ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides
⇒ Area of triangle ABC / Area of triangle DEF = BC2 / EF2
⇒ Area of triangle ABC / Area of triangle DEF = (2EF)2 / EF2
⇒ Area of triangle ABC / Area of triangle DEF = 4 / 1.
∴Ratio of the areas of triangle DEF and triangle ABC is 1 : 4.
Step-by-step explanation:
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