Question

Find the ratio of volume of cylinder. When the radius is halved, and the height is same to that of volume of cylinder.​

Answer 1

$\sf \underline {\underline{ANSWER}} \\ \\ \sf Given, \\ \: \: \: \: \: \: \: \: \: \: \: \sf original \: volume \: (v_{1}) = \pi{r}^{2} h \\ \sf \: \: \: \: \: \: \: \: \: \: \: reduced \: length \: (v _{2}) \: = \\ \\ \tt{ \star } \: \: radius \: is \: halved \\ \tt \star \: \: height \: is \: same \\ \\ \sf = \pi(\frac{r}{2} )^{2} h \\ \\ \\ \therefore \sf ratio \: = \frac{\pi \times r \times r \times h }{ \pi \times \frac{r}{2} \times \frac{r}{2} \times h} = \bf \red {1 : 4}$

Answer 2

Solution :—

We know that ,

Volume of Cylinder = πr²h

To find ,

The ratio of volume of cylinder, when the radius is halved, and the height is same to that of volume of ccylinder :-

Now , Given that ,

Radius is halved and the height is same.

So ,

$= > \pi( \frac{r}{2} )^{2}h$

Then , Ratio =

$= > \frac{\pi \times r \times r \times h}{\pi \times \frac{r}{2} \times \frac{r}{2} \times h }$

$= > \frac{1}{ \frac{1}{2} \times \frac{1}{2} } = \frac{1}{4}$

=> 1:4 ( Answer )