Chemistry, asked by nxmxn, 1 year ago

Find the ratio of volume of cylinder. When the radius is halved, and the height is same to that of volume of cylinder.​

Answers

Answered by Anonymous
1
 \sf \underline {\underline{ANSWER}} \\ \\ \sf Given, \\ \: \: \: \: \: \: \: \: \: \: \: \sf original \: volume \: (v_{1}) = \pi{r}^{2} h \\ \sf \: \: \: \: \: \: \: \: \: \: \: reduced \: length \: (v _{2}) \: = \\ \\ \tt{ \star } \: \: radius \: is \: halved \\ \tt \star \: \: height \: is \: same \\ \\ \sf = \pi(\frac{r}{2} )^{2} h \\ \\ \\ \therefore \sf ratio \: = \frac{\pi \times r \times r \times h }{ \pi \times \frac{r}{2} \times \frac{r}{2} \times h} = \bf \red {1 : 4}
Answered by Anonymous
3

Solution :—

We know that ,

Volume of Cylinder = πr²h

To find ,

The ratio of volume of cylinder, when the radius is halved, and the height is same to that of volume of ccylinder :-

Now , Given that ,

Radius is halved and the height is same.

So ,

 =  > \pi( \frac{r}{2} )^{2}h

Then , Ratio =

 =  > \frac{\pi \times r \times r \times h}{\pi \times  \frac{r}{2} \times  \frac{r}{2}  \times h  }

 =  >  \frac{1}{ \frac{1}{2}  \times  \frac{1}{2} }  =  \frac{1}{4}

=> 1:4 ( Answer )

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