Find the rational numbers between 1 upon 4 and 1 upon 5
Answers
Answer:
First rational no.
\begin{gathered} \frac{1}{2} ( \frac{1}{4} + \frac{1}{5} ) \\ \end{gathered}
2
1
(
4
1
+
5
1
)
\begin{gathered} \frac{1}{2} \times ( \frac{5 + 4}{20} ) \\ \end{gathered}
2
1
×(
20
5+4
)
[LCM of 4 and 5 is 20]
\begin{gathered} \frac{1}{2} \times \frac{9}{20} \\ \end{gathered}
2
1
×
20
9
\begin{gathered} \frac{9}{40} \\ \end{gathered}
40
9
Second rational no.
\begin{gathered} \frac{1}{2} \times ( \frac{9}{40} + \frac{1}{4}) \\ \end{gathered}
2
1
×(
40
9
+
4
1
)
\begin{gathered} \frac{1}{2} \times( \frac{9 + 10}{40} ) \\ \end{gathered}
2
1
×(
40
9+10
)
[LCM of 4 and 40 is 40]
\begin{gathered} \frac{1}{2} \times \frac{19}{40} \\ \end{gathered}
2
1
×
40
19
\begin{gathered} \frac{19}{80} \\ \end{gathered}
80
19
Third rational no.
\begin{gathered} \frac{1}{2} \times ( \frac{9}{40} + \frac{1}{5}) \\ \end{gathered}
2
1
×(
40
9
+
5
1
)
\begin{gathered} \frac{1}{2} \times( \frac{9 + 8}{40} ) \\ \end{gathered}
2
1
×(
40
9+8
)
[LCM of 5 and 40 is 40]
\begin{gathered} \frac{1}{2} \times \frac{17}{40} \\ \end{gathered}
2
1
×
40
17
\begin{gathered} \frac{17}{80} \\ \end{gathered}
80
17