Question

find the rational roots for the polynomial 4x^3+ 20x^2-23x+6​

Answer 1

Answer:

STEP1:Equation at the end of step 1

(((4 • (x3)) - (22•5x2)) - 23x) - 6 = 0

STEP 2 :

Equation at the end of step2:

((22x3 - (22•5x2)) - 23x) - 6 = 0

STEP3:Checking for a perfect cube

 3.1    4x3-20x2-23x-6  is not a perfect cube

Trying to factor by pulling out :

 3.2      Factoring:  4x3-20x2-23x-6 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -23x-6 

Group 2:  4x3-20x2 

Pull out from each group separately :

Group 1:   (23x+6) • (-1)

Group 2:   (x-5) • (4x2)

Answer 2

Answer:

answering just for free points