Question

find the rationalising factor for denominator of expression root 5 -2 I need explaination also remember​

Answer 1

Answer:

√5 + 2

Step-by-step explanation:

We have to Rationalise the denominator to remove the root from the denominator

That Can be done with the help of the property

$(x + y)(x - y) = x {}^{2} - y {}^{2}$

So we have √5 - 2 in the denominator

If we multiply it with √5 + 2 then

(√5 - 2)(√5 + 2 ) = (√5)^2 - 2^2 = 5 - 4 = 1

In That Way Root can be removed