find the reading of ideal ammeter connected in the given circuit diagram
Answers
Resistance :
R1 = 4 ohm
R2 = 12 ohm
R3 = 3 ohm
R4 = 6 ohm
R1, R2 and R3 are in parallel circuit
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/4 + 1/12 + 1/3
1/R = 3/12 + 1/12 + 4/12
1/R = 8/12
1/R = 2/3
R = 3/2
Total Resistance : R'
R + R4
3/2 + 6
3/2 + 12/2
15/2 ohm
Potential difference = V = 36v
Current = R' / V
15/2 ÷ 36 = 0.208 A
The reading of ammeter will 0.208 A.
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Explanation: