Find the real and imaginary part of sin z.
Answers
Answer:
that question is wrong
Step-by-step explanation:
because sin is an mathrmaical informational word
thry are definations
The real part is sin x cosh y and the imaginary part is cos x sinh y of sin z when z= x+iy.
Given that,
We have to find the real and imaginary part of sinz when z= x+iy
We know that,
What is imaginary number?
Imaginary numbers are those that, when squared, provide a negative number. The square root of negative numbers is another definition for them. A real number that is not zero and the imaginary unit i (sometimes referred to as "iota"), where i = √(-1) (or) i² = -1, are multiplied to create an imaginary number.
So,
sin z (where z= x+iy)
sin (x+iy)
We have a formula that is
sin (a+b) = sin a cosh b + i cos a sinh b
So,
sinz = sinxcoshy + icosxsinhy
The real part is sinxcoshy and the imaginary part is cosxsinhy
Therefore, The real part is sin x cosh y and the imaginary part is cos x sinh y of sin z when z= x+iy
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