Question

Find the real number whose product with irrational number, 4 - square root of 3 is 9

Answer 1

Answer:

9(4+sqrt(3))/13

Step-by-step explanation:

Let the real number in question is x.

x(4-sqrt(3)) = 9

x(4-sqrt(3))(4+sqrt(3)) = 9(4+sqrt(3))

x(4^2-(sqrt(3))^2) = 9(4+sqrt(3))

x(16-3) = 9(4+sqrt(3))

Therefore x = 9(4+sqrt(3))/13