Question

find the real numberd for which the system st2y+32 - du, 3x + y + 2z=dy. 2x+3y+z=12 has infinite number of solutions and hereesdue complety.​

Answer 1

Answer:

Correct option is D)

let x+2y+3z=14 ------------ (1)

3x+y+2z=11 ---------(2)

2x+3y+z=11 -----------(3)

multiplying eqn (2) by 2 and subtracting eqn(1) from it we get,

=5x+z=8 -------------(4)

again multiplying eqn (2) by 3 and subtracting eqn (3) from it we get,

= 7x+5z=22 ------------(5)

Now multiply eqn (4) by 5 and subtract eqn (5) from it we get

18x=18

∴x=1

substituting the x in eqn (4) we get the value of z as

= 5(1)+z=8

∴z=8−5=3

and substitute x and z in eqn (1) we get

1+2y+3(3)=14

2y=14−1−9=4

∴y=2

hence the answer is option D

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