Math, asked by raajonlyu1255, 7 months ago

Find the real part of (2+3i)(2-3i)(1+i)²

Answers

Answered by gowthamkaruppuswamy

7

Answer:

0

Step-by-step explanation:

= (2+3i)(2-3i)(1+i)^2

= 4+9(1+2i-1)

= 13(2i)

= 26i

= 0+26i

= 0 The real part will be 0

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