Find the real part of (2+3i)(2-3i)(1+i)²
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7
Answer:
0
Step-by-step explanation:
= (2+3i)(2-3i)(1+i)^2
= 4+9(1+2i-1)
= 13(2i)
= 26i
= 0+26i
= 0 The real part will be 0
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