Math, asked by kousernoorain10, 1 day ago

find the real root of the equation
{x}^{3}  +  {x}^{2}  + 3x + 4 = 0
near
x = - 1
using newton raphson method​

Answers

Answered by buddypau26
0

2x/3+3x/2+15x/5+20/5=0

2x+3x+15x+20/5=0

50/5=0

10=0

x=10

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