Question

find the real root of x2_x+4

Answer 1

x²-x+4

b²-4ac > 0

x=(-(-1)±√(〖(-1)〗^2-4(1)(4)))/(2(1))

x=(1±√(1-16))/2

x=(1±√(-15))/2

x=(1±√15)/2

x=(1-√15)/2  ,  (1+√15)/2