find the real roots of 4x^4 = 64
Answers
Answer:
hey mate here is ur answer
Step by Step Solution
= STEP 1 :
=Equation at the end of step 1
= 22x4 - 64
= STEP 2 :( NOTHING)
= STEP 3:
Pulling out like terms
3.1 Pull out like factors :
4x4 - 64 = 4 • (x4 - 16)
= Trying to factor as a Difference of Squares:
= 3.2 Factoring: x4 - 16
= Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
= Proof : (A+B) • (A-B) =
= A2 - AB + BA - B2 =
= A2 - AB + AB - B2 =
= A2 - B2
= Note : AB = BA is the commutative property of multiplication.
= Note : - AB + AB equals zero and is therefore eliminated from the expression.
= Check : 16 is the square of 4
= Check : x4 is the square of x2
= Factorization is : (x2 + 4) • (x2 - 4) HENCE SOLUTION
thank you
Answer: x = ± 2.
Explanation:
4x^4 = 64
=> x^4 = 16
=> x = ⁴√16
=> x = ± 2.