Question

find the real roots of the equation 2^2x²-7x+5=1.​

Answer 1

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$\star \: \: \underline \blue{solution} \blue{ : }$

${2}^{2 {x}^{2} - 7x + 5} = 1 \\ \longrightarrow \: {2}^{2 {x}^{2} - 7x + 5} = {2}^{0} \\ \longrightarrow \: 2 {x}^{2} - 7x + 5 = 0 \\ {\bold {\boxed{ x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a} }}} \\ \longrightarrow \: x = \frac{7 ± \sqrt{49 - 40} }{2 \times 2} \\ \longrightarrow \: x = \frac{7}{4 } ± \frac{3}{4} \\ \\ {\boxed {\huge {\mathfrak{x = \frac{5}{2} \: \: or \: \: x = 1}}}}$

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