Find the real roots of the equation 2^2x²-7x+5 = 1 I want step by step explanation.
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Step-by-step explanation:
2^2x^2 - 7x + 5 = 2^0 ( we can write 1=2^0 )
so ,
2x^2 -7x + 5 = 0
according to formula
real root of this equation is 5/2 , 1
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