find the real roots
of the equation
x^3+12x-12=0
Answers
Answered by
1
Given equation, x
2
+12x−12=0 and given root is 2
3
2
−
3
4
Simplifying the given roots, we can write root(r)=2
3
4
–2
3
2
Substituting x=r in the given equation, we can solve it as:
(2
3
4
–2
3
2
)
3
+12(2
3
4
–2
3
2
)−12
⟹2
4
−3⋅2
3
⋅2
3
1
+3⋅2
2
⋅2
3
2
−2
2
+3⋅2
3
⋅2
3
1
−3⋅2
2
⋅2
3
2
−12=16−4−12=0
Since the equation reduces to zero for x=r, we can say that r is the real root of the given equation.
Similar questions
+3hz+g=0 have a real root z=
3
p
+
3
q
when
3
pq
=−h
Using this for
x
3
+12x−12=0
From options
A) 2
3
2
−
3
5
3
16
3
−5
=−4
B) 2
3
2
+
3
5
3
16
3
5
=−4
C) 2
3
2
+
3
4
3
16
3
4
=4
=−4
D) 2
3
2
−
3
4
3
−16
3
4
=−4