find the real roots of xe raise to power x -3=0 using false position method
Answers
Step-by-step explanation:
f(x)=3x+sinx−e
x
=0
f(0.3)=3(0.3)+sin(0.3)−e
0.3
=−0.15433860091<0
f(0.4)=3(0.4)+sin(0.4)−e
0.4
=0.09759364467>0
By Regula-Falsi method
x
1
=
f(0.3)−f(0.4)
0.3f(0.4)−0.4f(0.3)
=0.36126194787
f(0.36126194787)>0
f(0.3)<0
Repeating the iteration process
x
2
=
f(0.36126194787)−f(0.3)
0.3f(0.36126194787)−0.36126194787f(0.3)
=0.3604389982
∴x=0.3604(to 4 d.p.)
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