Question

Find the real solution of the equation
tan−1√x(x+1)+sin−1√x2+x+1=π2

Answer 1

Answer:tan−1x(x+1)−−−−−−−√=π2−sin−1(x2+x+1)−−−−−−−−−−√

⇒tan−1x(x+1)−−−−−−−√=cos−1x2+x+1−−−−−−−−−√

⇒cos−11x2+x+1−−−−−−−√=cos−1x2+x+1−−−−−−−−−√

⇒x2+x+1=1

⇒x(x+1)=0

x=0,−1

Step-by-step explanation: