Question

find the real solution of the following equation​

Answer 1

Answer and Step-by-step explanation:

$2^{ ( x^{2} - 4x + 6 ) }$ = 8 = $2^{3}$

$x^{2} -4x + 6 = 3\\x^{2} -4x +3 = 0\\x^{2} - 3x -x + 3 = 0\\x(x-3) -1(x-3) = 0\\(x-1)(x-3)\\x = 1,3$