Math, asked by shendesomnath12, 2 months ago

find the real value of (2+i)x+(i-3)y=0​

Answers

Answered by chandan454380
0

Answer:

The answer is x=0,y=0

Step-by-step explanation:

 (2+i)x+(i-3)y=0\\

\Rightarrow (2x-3y)+i(x+y)=0+0i, write in the standard form

Now equate real parts and imaginary parts from both sides

\Rightarrow 2x-3y=0 and x+y=0

Solving these equations we get x=0,y=0

(Assumed that x and y are real)

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