Question

find the real value of (2+i)x+(i-3)y=0​

Answer 1

Answer:

The answer is $x=0,y=0$

Step-by-step explanation:

 $(2+i)x+(i-3)y=0$

$\Rightarrow (2x-3y)+i(x+y)=0+0i$, write in the standard form

Now equate real parts and imaginary parts from both sides

$\Rightarrow 2x-3y=0$ and $x+y=0$

Solving these equations we get $x=0,y=0$

(Assumed that x and y are real)