Find the real value of x and y if x -2 +(y -3)i / 1 +i = 1 -3i .
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Answer:
Given,
1+i
(x−2+i(y−3))
=1−3i
x−2+i(y−3)=1+i−3i(1+i)
(x−2)+i(−3+y)=4−2i
[
x−2=4
−3+y=−2
]
x−2=4⇒x=6
−3+y=−2⇒y=1
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