Find the real value(s) of 'a' for which the equation x2 + 2x + (a^2 +1) = 0 has real roots. Justify your answer.
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If an equation had real roots then,
D = b²- 4ac =0
let's put values,
2²-4(1)(a²-1) = 0
4-4a²+4 = 0
8-4a² = 0
4a² = 8
a² = 2
a= √2.
Hope it helps.
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