Question

find the real values of x and y for which
[ { ( x - 1 ) / 3 }+ { ( y - 1 ) / 3 -i } ] = i


i.e.

$( \frac{x - 1}{3 + i} + \frac{y - 1}{3 - i} ) = \: i$
remember give only correct answer with step by step explanation ​

Answer 1

Step-by-step explanation:

(x-1)(3-i)+(y-1)(3+1)=I

3x-3-xi+i+3y-3+y-1=I

3x+3y-6-xi+i-1=I

I.e i=1say

3x+3y-6-x+1-1=I

2x+3y-6=i

Answer 2

Question ⤵️

find the real values of x and y for which

[ { ( x - 1 ) / 3 }+ { ( y - 1 ) / 3 -i } ] = i

Answer ⤵️

Let equation = (2x−y)(ax+by)

At x=y=1;Q=2

⇒2=1(a+b)⇒a+b=2

At x=−16y=1;Q=0

⇒(b−a)=0⇒a=b=1

∴Q=(2x−y)(x+y)=2x²+xy−y²

Hope it helps you ✌️

Step-by-step explanation:

Question is not fully understanding sorry

but I tried to answer you

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