Question

find the real values of x and y if (3+i) (x+iy) =2+14i​

Answer 1

Answer:

(x−iy)(3+5i)=(3x+5y)+i(5x−3y)

It is given that (x−iy)(3+5i) is the conjugate of −6−24i

.

(x−iy)(3+5i)=

−6−24i

(3x+5y)+i(5x−3y)=−6+24i

3x+5y=−6 and 5x−3y=24

Solving these equations, we get, x=3 and y=−3.