Question

find the reciprocal of cos(90-x)°​

Answer 1

Answer:

cos(90-x)°=1/sin(x)°

Step-by-step explanation:

There are three angles in a triangle. Let one be 90°, other be x and the last is 90°-x [180° - (90° + x) = last angle ]. The cos of (90°- x) is the side adjacent to it / hypotenuse. But the side adjacent to 90°- x would be opposite to x. Sin (x)° would be opposite side to x ( side adjacent to 90°- x) / hypotenuse. Thus, cos (90-x)°= sin (x) °. Thus reciprocal of

cos (90-x)° would be 1/sin(x)°

Answer 2

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$1/ \sin(x)$°