Question

find the reciprocal of sum of (1/5)-¹ and(3/5)-¹
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Answer 1

Answer:

your answer is 20/3

Answer 2

Given,

The given fractions are $(\frac{1}{5} )^{-1}$ and $(\frac{3}{5} )^{-1}$

As we know that the formula

$(\frac{a}{b}) ^{-1} =\frac{b}{a}$

$(\frac{1}{5} )^{-1}$  can be written as $\frac{5}{1}$

$(\frac{3}{5} )^{-1}$ can be written as $\frac{5}{3}$

Sum of  $\frac{5}{1}$ and  $\frac{5}{3}$ is

$5+\frac{5}{3}$

$=\frac{15+5}{3}$

$=\frac{20}{3}$

Reciprocal of $\frac{20}{3}$ is $\frac{3}{20}$