Find the recoil velocity of gun of mass 2kg from which a bullet of 20 g is fired with a velocity of 200m/s
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Given m1= 2 kg, v1 =? , m2= 20 x 10∧-3 kg, v2=200m/s
According to the law of linear momentum,
m1 x v1=m2 x v2
2 x v1 = 20 x 10∧-3 x 200
v1= 2 x 10∧-2 x 2 x 10∧2 / 2
v1= 2m/s
Explanation:
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