Math, asked by zobiyatahseen2006, 4 months ago

find the reduced form of the ratio of the first quantity to second quantity

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Answered by itzFaReboy
4

7 min 20 sec = 420 + 20 = 440 second

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2Required ratio = (440 /2) /(306/2)

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2Required ratio = (440 /2) /(306/2)= 220 / 153

7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2Required ratio = (440 /2) /(306/2)= 220 / 153= 220 : 153

accha lga to ek like kr dena.................

Answered by ammu2116
1

Answer:

hey friend can I know ur birth year...

why because I am also September..

please answer friend

waiting.....

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