find the reduced form of the ratio of the first quantity to second quantity
Answers
7 min 20 sec = 420 + 20 = 440 second
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2Required ratio = (440 /2) /(306/2)
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2Required ratio = (440 /2) /(306/2)= 220 / 153
7 min 20 sec = 420 + 20 = 440 second5 min 6 sec = 300 + 6 = 306 second440 = 2 × 2 × 2 × 5 × 11306 = 2 × 3 × 3 × 3 × 17HCF = 2Required ratio = (440 /2) /(306/2)= 220 / 153= 220 : 153
accha lga to ek like kr dena.................
Answer:
hey friend can I know ur birth year...
why because I am also September..
please answer friend
waiting.....